you want us to simplify [tex]\frac{3x^2-3x}{x^2-9x}-3[/tex]
first, factor top and bottom
[tex]3x^2-3x=3x(x-1)[/tex]
[tex]x^2-9x=x(x-9)[/tex]
so we have
[tex]\frac{3x(x-1)}{x(x-9)}-3=[/tex]
[tex]\frac{3(x-1)}{x-9}-3[/tex]
we want to combine fractions so multiply 3 by [tex]\frac{x-9}{x-9}[/tex]
[tex]\frac{3(x-1)}{x-9}-\frac{3(x-9)}{x-9}=[/tex]
[tex]\frac{3(x-1)-3(x-9)}{x-9}=[/tex]
[tex]\frac{3x-3-3x+27}{x-9}=[/tex]
[tex]\frac{24}{x-9}[/tex]
the simplified answer is [tex]\frac{24}{x-9}[/tex]
