Answer:
The probability is [tex]\frac{1}{12}[/tex]
Step-by-step explanation:
Define the events [tex]A[/tex] and [tex]B[/tex] as the events "rolling a 2" and "rolling an odd number", respectively. Notice that the result of every rolling is independent of the previous results, so the event [tex] A\cap B[/tex] describes the phenomenon we are analazying.
On the other hand, we have that the probability of rolling a 2 is [tex]\frac{1}{6}[/tex] and the probability of rolling an odd number is [tex]\frac{1}{2}[/tex], thus
[tex] P(A\cap B) = P(A)\cdot P(B) = \frac{1}{6}\cdot \frac{1}{2} = \frac{1}{12} [/tex].
