The normal force that the incline exerts on the block will be equal in magnitude to the sum of the following:
1. the component of weight directed into the incline
2. the component of the force pressing the block against the incline
normal force = mg cos(43) + F sin(43)
normal force = (17 kg) (9.80 m/s^2) cos(43) + 175 N sin(43)
normal force = 241 N
The magnitude of the normal force that the incline exerts on the block is 241 N
