angle = 5°
Acceleration = a = g x Sin(θ) where g = 9.8m/s² = 9.8*Sin(6) = 0.854 m/s² ,
As coasting comes to a stop:
v = a x t = 0
t = v/a = 34/0.854 = 39.8 seconds
The distance traveled is:
d = (vf-vi)t - (1/2)at² = 34 x 39.8 - (1/2)(0.854)(39.8)² =
1353.2 -676.4
= 676.8 m
