Respuesta :
Event: Probability: A. Too much enamel 0.18 B. Too little enamel 0.24 C. Uneven application 0.33 D. No defects noted 0.47
let P(AC) = x, P(BC) = y, then P(A) + P(B) + P(C) - (x+y) = 1-0.47 = 0.53 x+y = 0.22
3. The probability of paint defects that results to an improper amount of paint and uneven application?
P(A U B U C) = 0.53
4. the probability of a paint defect that results to
the proper amount of paint, but uneven application?
P(C) - P(AC) - P(BC) = 0.47 - 0.22 = 0.25
A and B are disjoint so P(ABC) = 0, but you can have P(AC) and P(BC). you can't compute these separately here, but you can compute P(AC) + P(BC). By the way, P(AC) eg is just an abbreviated version of P(A∩C).
let P(AC) = x, P(BC) = y, then P(A) + P(B) + P(C) - (x+y) = 1-0.47 = 0.53 x+y = 0.22
3. The probability of paint defects that results to an improper amount of paint and uneven application?
P(A U B U C) = 0.53
4. the probability of a paint defect that results to
the proper amount of paint, but uneven application?
P(C) - P(AC) - P(BC) = 0.47 - 0.22 = 0.25
A and B are disjoint so P(ABC) = 0, but you can have P(AC) and P(BC). you can't compute these separately here, but you can compute P(AC) + P(BC). By the way, P(AC) eg is just an abbreviated version of P(A∩C).
From the information given, the probability of a paint defect will be 0.56.
How to calculate the probability
The following information are given
- Too much enamel = 0.21
- Too little enamel = 0.26
- Uneven application = 0.31
- No defects noted = 0.44
The probability of a paint defect will be:
= 1- ( probability of no defects noted)
= 1 - 0.44
= 0.56
Therefore, the probability of a paint defect will be 0.56.
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