Respuesta :


So first we have to find a common denominator, in this case it is simple because 18 works. So now we have to make 1/9 into ?/18, to do this we multiply 1/9 by 2, so now we have 2/18 + 2/3 + 5/18. To make 2/3 into ?/18 we have to multiply by 6, so now we have 2/18 + 12/18 + 5/18. Now you add all the numerators (top numbers) together and we get 19/18, which is the same as 1  1/18

ANSWER: 19/18 or 1  1/18. 

Feel free to ask any questions about my explanation if you need it(:

The sum of the fractions [tex]\dfrac{1}{9},\dfrac{2}{3},\dfrac{5}{{18}}[/tex] is [tex]\boxed{\frac{{{\mathbf{19}}}}{{{\mathbf{18}}}}}[/tex].

Further explanation:  

Given:

The given fractions are [tex]\dfrac{1}{9},\dfrac{2}{3},\dfrac{5}{{18}}[/tex].

Step by step explanation:

Step 1:

First we make the denominator same of the given fraction.

The equivalent fraction of [tex]\dfrac{1}{9}[/tex] can be calculated as,

[tex]\dfrac{{1 \times 2}}{{9 \times 2}} = \dfrac{2}{{18}}[/tex]  

The equivalent fraction of [tex]\dfrac{2}{3}[/tex] can be calculated as,

[tex]\dfrac{{2 \times 3}}{{3 \times 3}} = \dfrac{6}{9}[/tex]  

The equivalent fraction of [tex]\dfrac{5}{{18}}[/tex] can be calculated as,

[tex]\dfrac{{5 \times 1}}{{18 \times 1}} = \dfrac{5}{{18}}[/tex]  

Step 2:

We know the sum of the given fractions and the sum of the equivalent fractions would be same.

Now find the sum of the equivalent fraction to find the sum of the given fractions [tex]\dfrac{1}{9},\dfrac{2}{3},\dfrac{5}{{18}}[/tex] as,

[tex]\begin{aligned}\frac{2}{{18}} + \frac{{12}}{{18}} + \frac{5}{{18}} &= \frac{{2 + 12 + 5}}{{18}} \\&= \frac{{19}}{{18}} \\\end{aligned}[/tex]    

Therefore, the sum of the fractions [tex]\dfrac{1}{9},\dfrac{2}{3},\dfrac{5}{{18}}[/tex] is [tex]\dfrac{{19}}{{18}}[/tex].

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Fractions

Keywords: sum, equivalent, fraction, denominator, numerator, number, division, multiplication, addition, difference, product, natural number