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Pipe A can fill a tank in 8 hours and Pipe B can fill the tank in 10 hours. With the tank empty, Pipe A and Pipe B are turned on. How long will each pipe run before the tank is full? Round to the nearest tenth.

Respuesta :

MathPhys

Answer:

4.4 hr

Step-by-step explanation:

The flow rate through each pipe is equal to the volume of the tank divided by the time it takes to fill the tank. Working together, the total flow rate is the sum of the individual flow rates.

Let's assume the volume of the tank is 80 gallons (80 is a multiple of 8 and 10, so this will make the math a little easier).

The flow rate of Pipe A is 80 gal / 8 hr = 10 gal/hr.

The flow rate of Pipe B is 80 gal / 10 hr = 8 hal/hr.

The flow rate of both pipes together is 10 gal/hr + 8 gal/hr = 18 gal/hr.

Therefore, the time to fill the tank is:

18 gal/hr × t = 80 gal

t = 80/18 hr

t ≈ 4.4 hr