hannahgoff
hannahgoff
18-08-2017
Mathematics
contestada
what is the factored version of 8-r^3
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Аноним
Аноним
18-08-2017
To factor a cube (a^3-b^3) = (a-b)(a^2+ab+b^2)
8 is the cube of 2
r^3 is the cube of r.
So, a is 2 and b is r
(2-r)(2^2+2r+r^2)
(2-r)(4+2r+r^2)
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amberlparsons00
amberlparsons00
18-08-2017
The answer to your question is (2-r)(4+2r+r^2)
Answer Link
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