Let us consider the possibility of the first person not having a license, which is:
3/7
Now, after a person has been chosen, there will be 6 people remaining. Assuming that the first person chosen did not have a license, there will be 2 people left in the group without a license. So, the probability of choosing a person without a license the second time will be:
2/6 = 1/3
In probability, when two events occur together (the word "and" is used), multiplication is carried out. Therefore, we multiply the two probabilities to get:
3/7 * 1/3 = 1/21
The probability of choosing two people without a license is 1/21.
