Respuesta :
Given yo = initial height the ball was thrown from.
Given vo = the initial velocity of the ball thrown
y = yo + (vo)t -16t^2 where t = time.
This is a parabola opening downward.
There is no y intercept as the ball is thrown upwards upwards not necessarily straight vertically.
The x-intercepts occur when the ball reaches the level the ball was thrown from or the ground.
Given vo = the initial velocity of the ball thrown
y = yo + (vo)t -16t^2 where t = time.
This is a parabola opening downward.
There is no y intercept as the ball is thrown upwards upwards not necessarily straight vertically.
The x-intercepts occur when the ball reaches the level the ball was thrown from or the ground.
The x and y-intercepts represent the time at which the object will hit the ground and the initial height of the object respectively.
As we know the relation between height and time for a projectile motion,
[tex]h = h'+ut - \frac{1}{2} g t^2[/tex].......eq1
Where h' is the initial height of the object.
Here, the y-axis represents the height
And the x-axis represents the time.
What is a projectile motion?
Projectile motion is the motion of an object projected vertically upward into the air and moving under the influence of gravity.
For y-intercept put t= 0 in eq1
Eq1 becomes h =h'
So, the y-intercept represents the initial height (if any)
For x-intercept put h = 0 in eq1
We get a quadratic equation having two distinct values of t
These values represent the time at which an object will hit the ground.
Therefore, the x and y-intercepts represent the time at which the object will hit the ground and the initial height of the object respectively.
To get more about projectile motion visit:
https://brainly.com/question/24216590