Answer:
The amplitude of given function is [tex]\frac{1}{2}[/tex].
Step-by-step explanation:
The given function is
[tex]y=\frac{1}{2}\sin 2x[/tex] .... (1)
The standard form of sine function is
[tex]y=A\sin(Bx+C)+D[/tex] ..... (2)
Where, A is amplitude, [tex]\frac{2\pi}{B}[/tex] is period, C is phase shift and D is mid line.
On comparing (1) and (2), we get
[tex]A=\frac{1}{2}[/tex]
Therefore the amplitude of given function is [tex]\frac{1}{2}[/tex].
