I can give you an example and if you have more questions you can always ask :)
Let's say we are given trinomial
x^2+5x+6
when factoring trinomials that no not have an "a value" (or basically a number in front of the x) then you can just find 2 numbers that adds up to the "b value" (number in the middle) that also multiply to the "c value" or the last number on the very end.
So for our example x^2+5x+6
Find numbers that adds up to 5 and multiply to 6
3+2=5 and 3•5=6
so we "split" the x^2 and get
(x+3)(x+2)
if we were asked to find what x equals we would set each expression equal to zero and solve:
(x+3)=0
Subtract 3 on both sides
x= -3
(x+2)=0
Subtract 2
x= -2
Hope this helps !!