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The length of a swimming pool is 4 feet longer than 2 times it's width. If the perimeter of the pool is 128 feet, what is the width of the pool

Respuesta :

zrh2sfo

Let L = the length, and W = the width.

L = 2W ......(1)

(L+2)(W+2) - LW = 100 => 2W+2L+4 = 100 ......(2)

Plug (1) into (2), and solve for L,

3L = 96

L = 32 feet

W = L/2 = 16 feet

Answer: The length of the pool is 32 feet, and the width is 16 feet.

morou
x equals 31.  so the width is 62 feet.  the length is then 66 feet 

to find this, write out all your terms (2x,2x,+4) into an equation (2x+2x+4=128) from there, simplify and solve. 

4x+4=128
-4        -4
4x=124
---   -----   <--- division
4       4
x=31

then you multiply 31 by 2 to get the width and add 4 to get the length

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