Respuesta :
Answer:
Common difference of the sequence is = [tex]\frac{1}{12}[/tex]
Step-by-step explanation:
Common difference of any sequence is defined by the difference between a term and its successive term.
Sequence is [tex]\frac{1}{6}, \frac{1}{4},\frac{1}{3}.....[/tex]
Common difference = [tex]T_{2}-T_{1}=\frac{1}{4}-\frac{1}{6}[/tex]
= [tex]\frac{2}{24}[/tex]
= [tex]\frac{1}{12}[/tex]
Now we will do the same for [tex]T_{3}[/tex] and [tex]T_{2}[/tex]
[tex]T_{3}-T_{2}[/tex] = [tex]\frac{1}{3}-\frac{1}{4}[/tex]
= [tex]\frac{4-3}{12}[/tex]
= [tex]\frac{1}{12}[/tex]
Therefore, answer is [tex]\frac{1}{12}[/tex]
