Respuesta :

[tex]\bf f(x)=ln(x^3+e^{4x})\implies \cfrac{df}{dx}=\cfrac{\frac{d}{dx}[x^3+e^{4x}]}{x^3+e^{4x}} \\\\\\ \cfrac{df}{dx}=\cfrac{3x^2+\frac{d}{dx}[4x]e^{4x}}{x^3+e^{4x}}\implies \cfrac{df}{dx}=\cfrac{3x^2+4e^{4x}}{x^3+e^{4x}}[/tex]