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In January 2000, i was one more than 11 times-as old as my daughter emma. In January 2009, i was 7 more than 3 times as old as her

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mhanifa

Emma was 3 in 2000 and the father was 34

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Let's define F as the father's age and E as Emma's age in January 2000.

According to the question, the father's age in January 2000 was one more than 11 times Emma's age, which gives us the first equation:

  • F = 11E + 1

In January 2009, the father was seven more than three times as old as Emma. By this time, both would have aged by 9 years, so the second equation is:

  • F + 9 = 3(E + 9) + 7

Substitute F from the first equation into the second equation.

  • 11E + 1 + 9 = 3E + 27 + 7

Simplify and solve for E:

  • 11E + 10 = 3E + 34
  • 11E - 3E = 34 - 10
  • 8E = 24
  • E = 3

Substitute E into the first equation to find F:

  • F = 11(3) + 1
  • F = 34

Therefore, Emma was 3 years old in January 2000, and thus she was born in 1997, and the father was 34 years old in January 2000.

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