Heat energy is often measured in calories and 1 calorie (cal) = 4.184 Joule (J). It is desired to design a heating element to boil a certain amount of water in 2 min requiring 40 kcal heat energy. If the heating element is to operate at 110 V, calculate its current and power ratings

Respuesta :

Answer:

7.17sec J its current and power ratings

Explanation:

p=E/T

=2 min/40kcal

=120sec/1,67,360J