richardsonkim0
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can someone please help with this?
In 2015, the price of a business math text rose to $150. This is 8% more than the 2014 price. What was the old selling price? (Round to the nearest cent.)

Selling price $

Respuesta :

the old price is "x"

now, if the new price is 150 and is 8% more, that means this new price is the 108% of the old price

so  [tex]\bf \begin{array}{ccllll} amount&\%\\ \textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\ x&100\\ 150&108 \end{array}\implies \cfrac{x}{150}=\cfrac{100}{108}[/tex]

solve for "x"

Answer:

The old price was approximately $ 138.89.

Step-by-step explanation:

Let x be the old selling price of the business math,

Given,

The price is increased by 8 %,

So, the new price = Old price + 8 % of old price

= x + 8 % of x

= x + 0.08x

= 1.08x

According to the question,

[tex]1.08x = 150[/tex]

[tex]\implies x = \frac{150}{1.08}=138.8889\approx 138.89[/tex]

Hence, the old price was approximately $ 138.89.

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