Respuesta :
Answer: 1 mol of [tex]AlCl_3[/tex] will be produced from this reaction.
Explanation: Reaction follows,
[tex]3Al+3NH_4ClO_4\rightarrow Al_2O_3+AlCl_3+3NO+6H_2Oc[/tex]
As seen from the balanced chemical equation above, we get
For every 3 moles of Aluminium and 3 moles of [tex]NH_4ClO_4[/tex], 1 mole of [tex]Al_2O_3[/tex] is formed.
For every 3 moles of Aluminium and 3 moles of [tex]NH_4ClO_4[/tex], 1 mole of [tex]AlCl_3[/tex] is formed.
For every 3 moles of Aluminium and 3 moles of [tex]NH_4ClO_4[/tex], 3 moles of [tex]NO[/tex] is formed.
For every 3 moles of Aluminium and 3 moles of [tex]NH_4ClO_4[/tex], 6 moles of [tex]H_2O[/tex] is formed.
