Respuesta :

mreijepatmat
Let's apply the law of sine  to calculate angle C
sin(81)/26 =  sin(C)/28
0.1646 = sin(C)/28 and sin(C) =1.063. Sine sin(α) cannot be > than 1, so this triangle is invalid

Answer:

Step-by-step explanation:

Alright, lets get started.

Side b = 26

Side c = 28

Angle B = 81

Using sin law

[tex]\frac{sinB}{b}=\frac{sinC}{c}[/tex]

[tex]\frac{sin81}{26}=\frac{sinC}{28}[/tex]

[tex]sinC= \frac{28sin81}{26}[/tex]

[tex]sinC= \frac{28*0.98769}{26}=1.06[/tex]

We got sin C value 1.06 which is more than 1, that is not possible because its out of range for sin function.

It means triangle is not possible.

Hence Zero triangle.   :    Answer

Hpe it will help :)

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