Answer:
Option D is the correct answer.
Step-by-step explanation:
[tex]-2\frac{2}{3}=-\frac{8}{3}\\\\-5\frac{1}{3}=-\frac{16}{3}\\\\-10\frac{2}{3}=-\frac{32}{3}\\\\-21\frac{1}{3}=-\frac{64}{3}[/tex]
So the series is
[tex]-\frac{8}{3},-\frac{16}{3},-\frac{32}{3},-\frac{64}{3}.............[/tex]
[tex]\frac{-\frac{16}{3}}{-\frac{8}{3}}=2\\\\\frac{-\frac{32}{3}}{-\frac{16}{3}}=2\\\\\frac{-\frac{64}{3}}{-\frac{32}{3}}=2[/tex]
We can see that each term is twice of the previous term
So, f(x + 1) = 2f(x)
Option D is the correct answer.
