Respuesta :
PV = nRT --> n = PV/RT
n = (3)(.117)/(.0821)(353)
n = .351/28.98 = 0.0121 moles XeF4
n = (3)(.117)/(.0821)(353)
n = .351/28.98 = 0.0121 moles XeF4
Answer:
Moles of Xenon present = 0.012
Explanation:
Given:
Volume of container, V = 3.0 L
Temperature of Xe gas, T = 80 C
Pressure of Xe gas, P = 0.117 atm
To determine:
The moles of Xe gas
Explanation:
Based on the ideal gas equation:
[tex]PV = nRT[/tex]
where n = number of moles of the gas
R = gas constant = 0.0821 L.atm/mol-K
[tex]n = \frac{PV}{RT} = \frac{0.117atm*3.0 L}{0.0821 Latm/mol-K*(80+273)K} =0.012\ moles[/tex]