This is my next Trigonometry question I am needed help on- I just want to be sure I've got it right, or if not, then the steps I need to take to get it right. Thank you.

This is my next Trigonometry question I am needed help on I just want to be sure Ive got it right or if not then the steps I need to take to get it right Thank class=

Respuesta :

[tex]\bf \begin{array}{clclll} (-2&,&9)\\ \uparrow &&\uparrow \\ x&&y\\ a&&b \end{array} \\\\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\implies c=\sqrt{(-2)^2+(9)^2} \\\\\\ c=\sqrt{85}\impliedby \begin{array}{llll} \textit{hypotenuse/radius is just a unit}\\ \textit{thus, is never negative} \end{array} \\\\\\ cos(\theta)=\cfrac{adjacent}{hypotenuse}\implies cos(\theta)=\cfrac{a}{c}\implies cos(\theta)=\cfrac{-2}{\sqrt{85}}\\\\ -------------------------------\\\\[/tex]

[tex]\bf \textit{now, let's rationalize the denominator} \\\\\\ \cfrac{-2}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies \cfrac{-2\sqrt{85}}{85}[/tex]