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Suppose the pressure on 60 cubic meters of gas is raised from 1 atmosphere to 3 atmospheres. What new volume does the gas occupy? Pliz help me in this one pliz

Respuesta :

mergl
(p1*v1)=(p2*v2)
p1=1 atm
p2=3 atm
v1=60
v2=(p1*v1)/(p2)
v2=(1*60)/(3)
v2=60/3
v2=20 cubic meters

The process is an isothermal process. Then the product of PV will remain constant. Then the new volume will be 20 cubic meters.

What is an ideal gas equation?

The ideal gas equation is given below.

[tex]PV = mRT[/tex]

P = pressure

V = volume

m = mass of the gas

R = gas constant

T = temperature

Suppose the pressure on 60 cubic meters of gas is raised from 1 atmosphere to 3 atmospheres.

The process is an isothermal process. Then the product of PV will remain constant.

Let the new volume be x. Then we have

3x = 60

 x = 20 cubic meters

More about the ideal gas equation link is given below.

https://brainly.com/question/4147359

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