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At one of New York’s traffic signals, if more than 17 cars are held up at the intersection, a traffic officer will intervene and direct the traffic. The hourly traffic pattern from 12:00 p.m. to 10:00 p.m. mimics the random numbers generated between 5 and 25. (This holds true if there are no external factors such as accidents or car breakdowns.) Scenario Hour Number of Cars Held Up at Intersection A noon−1:00 p.m. 16 B 1:00−2:00 p.m. 24 C 2:00−3:00 p.m. 6 D 3:00−4:00 p.m. 21 E 4:00−5:00 p.m. 15 F 5:00−6:00 p.m. 24 G 6:00−7:00 p.m. 9 H 7:00−8:00 p.m. 9 I 8:00−9:00 p.m. 9 Based on the data in the table, which scenarios would require a traffic cop? A, B, and E B, D, and F G, H, and I A, C, and E

Respuesta :

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B,D, and F would be the times requiring a traffic officer

Answer:

The answer is : B,D and F will require a traffic cop

Step-by-step explanation:

To find scenarios which require a traffic cop or not we need to find the no. of cars standing up at the intersection

So, no. of cars standing at the intersection of three traffic lights = minimum of no. of cars at all the three traffic lights

  • For scenario A,B and E , no. of cars at intersection = min { no. of cars at A, no. of cars at B , no. of cars at E}

= min { 16,24,15 } = 15 < 17 . So, no traffic cop required.

  • For scenario B,D and F , no. of cars at intersection = min { no. of cars at B, no. of cars at D, no. of cars at F}

= min { 24,21,24 } = 21 > 17 . So, traffic cop is required

  • For scenario G,H and I , no. of cars at intersection = min { no. of cars at G, no. of cars at H , no. of cars at I}

= min { 9,9,9 } = 9 < 17 . So, no traffic cop required

  • For scenario A,C and E , no. of cars at intersection = min { no. of cars at A, no. of cars at C , no. of cars at E}

= min { 16,6,15 } = 6 < 17 . So, no traffic cop required

Hence, the scenario which requires a traffic cop is one at which intersection of no. of cars is greater than 17 so our required scenario is B,D and F