Answer:
[tex]8 *\sqrt{ 6}[/tex] - 1 [tex]\sqrt{2}[/tex].
Step-by-step explanation:
Given : 4 times square root 24 minus 4 square root 8 plus square root of 98.
To find : Simplify .
Solution : We have given statement .
According to questions :
4 times square root 24 = [tex]4 *\sqrt{24}[/tex].
4 square root 8 = [tex]4 *\sqrt{8}[/tex].
Square root of 98 = [tex]\sqrt{98}[/tex].
Then
[tex]4 *\sqrt{24}[/tex] - [tex]4 *\sqrt{8}[/tex] + [tex]\sqrt{98}[/tex].
We can write 24 as 4 *6 and 8 as 4 *2 and 98 as 49 *2
[tex]4 *\sqrt{4 * 6}[/tex] - [tex]4 *\sqrt{4 *2}[/tex] + [tex]\sqrt{49 * 2}[/tex].
On solving square root.
[tex]4 * 2*\sqrt{ 6}[/tex] - [tex]4 * 2 *\sqrt{2}[/tex] + 7* [tex]\sqrt{2}[/tex].
[tex]8 *\sqrt{ 6}[/tex] - [tex]8*\sqrt{2}[/tex] + 7* [tex]\sqrt{2}[/tex].
[tex]8 *\sqrt{ 6}[/tex] - ( 8 - 7) [tex]\sqrt{2}[/tex].
[tex]8 *\sqrt{ 6}[/tex] - 1 [tex]\sqrt{2}[/tex].
Therefore, [tex]8 *\sqrt{ 6}[/tex] - 1 [tex]\sqrt{2}[/tex].
