Respuesta :
The equilibrium lies far to the right so that products are very heavily favored.
H₂SO₄ → 2H⁺ + SO₄²⁻
Cl₃C-COOH → Cl₃C-COO⁻ + H⁺
H₂SO₄ → 2H⁺ + SO₄²⁻
Cl₃C-COOH → Cl₃C-COO⁻ + H⁺
Answer: The equilibrium lies far to the right so that products are very heavily favored.
Explanation:
Strong acids are defined as acids with high concentration of [tex]H^+[/tex] ion in their aqueous solution. They get easily dissociate in their aqueous solution.
[tex]HA\rightleftharpoons H^++A^-[/tex]
[tex]K_a=\frac{[H^+][A^-]}{[HA]}[/tex]
Generally, value of K_a of strong acids are greater than 1.
[tex]K_a>1[/tex]
[tex]K_a>\frac{[H^+][A^-]}{[HA]}[/tex]
So, to satisfy this above condition concentrations:
[tex][HA]<[H^+]\times [A^-][/tex]
Hence, the correct answer is :The equilibrium lies far to the right so that products are very heavily favored.