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The angle of elevation to the top of a very tall building is found to be 13° from the ground at a distance of 1 mi from the base of the building. Using this information, find the height h of the building. (Round your answer to the nearest foot.)

Respuesta :

mergl
tan(Θ)=(h/distance from base)
Θ=13 degrees, 1mile=5280 ft
tan(13)=(h/5280 ft)
5280tan(13)=h
h=1218.984049
h=1219 ft
ankitprmr2

Answer:

h = 1219ft

Step-by-step explanation:

Given :

Angle of elevation from the ground = [tex]13^{\circ}[/tex]

Distance = 1 mile = 5280ft

Calculation :

Let h be the height of the building.

[tex]\rm tan(13^{\circ}) = \dfrac {h}{5280}[/tex]

h = 1218.98ft

h = 1219ft (nearest foot)

For more information, refer the link given below

https://brainly.com/question/22986150?referrer=searchResults

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