Respuesta :
The balance chemical reaction is:
6 Li(s) + N2(g) → 2 Li3N(s)
We use the amount of the Lithium reactant and the relations of the substances from the reaction to calculate the amount of product produced. We do as follows:
1.75 mol Li ( 2 mol Li3N / 6 mol Li ) (34.83 g / mol) = 20.32 g Li
6 Li(s) + N2(g) → 2 Li3N(s)
We use the amount of the Lithium reactant and the relations of the substances from the reaction to calculate the amount of product produced. We do as follows:
1.75 mol Li ( 2 mol Li3N / 6 mol Li ) (34.83 g / mol) = 20.32 g Li
From the 1.75 moles of Li, the [tex]\rm Li_3N[/tex] formed is 20.317 grams.
The formation equation for [tex]\rm Li_3N[/tex] will be:
[tex]\rm 6\;Li\;+\;N_2\;\rightarrow\;2\;Li_3N[/tex]
For 6 moles of Li, there will be 2 moles of [tex]\rm Li_3N[/tex].
For 1.75 moles of Li, [tex]\rm Li_3N[/tex] will be:
= [tex]\rm \dfrac{2}{6} \;\times\;1.75[/tex]
= 0.583 moles.
The molecular mass of [tex]\rm Li_3N[/tex] is 34.83 g/mol.
moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
weight = moles [tex]\times[/tex] molecular weight
weight of [tex]\rm Li_3N[/tex] formed = 0.583 [tex]\times[/tex] 34.83 grams
weight of [tex]\rm Li_3N[/tex] formed = 20.317 grams.
The [tex]\rm Li_3N[/tex] formed is 20.317 grams.
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https://brainly.com/question/20290065
