mrqusai mrqusai

16-06-2017
Mathematics

contestada

evaluate the integral
\int (3t-2)/(t-1)dt
please which method i should use

Respuesta :

LammettHash LammettHash

18-06-2017

[tex]\dfrac{3t-2}{t-1}=\dfrac{3(t-1)+1}{t-1}=3+\dfrac1{t-1}[/tex]

[tex]\displaystyle\int\frac{3t-2}{t-1}\,\mathrm dt=3\int\mathrm dt+\int\frac{\mathrm dt}{t-1}=3t+\ln|t-1|+C[/tex]

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