tygatez
contestada

Which is the equation of a trend line that passes through the points (3, 95) and (11, 12)? Round values to the nearest ten-thousandths.

Respuesta :

calculista

Step 1

we know that

The formula to calculate the slope between two points is equal to

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

we have

[tex]A(3,95)\ B(11,12)[/tex]

Substitute the values

[tex]m=\frac{12-95}{11-3}[/tex]

[tex]m=\frac{-83}{8}[/tex]

[tex]m=-\frac{83}{8}[/tex]

Step 2

Find the equation of the line in point-slope form

[tex]y-y1=m(x-x1)[/tex]

In this problem we have

[tex](x1,y1)=B(11,12)[/tex]

[tex]m=-\frac{83}{8}[/tex]

substitute

[tex]y-12=-\frac{83}{8}(x-11)[/tex]

[tex]y=-\frac{83}{8}x+\frac{83}{8}11+12[/tex]

[tex]y=-10.375x+126.125[/tex]

therefore

the answer is

[tex]y=-10.375x+126.125[/tex]

The equation of the line that passes through the points (3, 95) and (11, 12) is 83x + 8y = 817.

Equation of line

The standard form of the equation of line passes through the point (x, y) and (x1, y1).

[tex]\rm y-y_1=m(x-x_1)[/tex]

Where m is the slope of the line.

The equation of a trend line that passes through the points (3, 95) and (11, 12)?

The slope of the line is;

[tex]\rm m=\dfrac{y_2-y_1}{x_2-x_1}\\\\m=\dfrac{12-95}{11-3}\\\\m =\dfrac{-83}{8}[/tex]

The equation of line passes through (11, 12) is;

[tex]\rm y-y_1=m(x-x_1)\\\\y-12=\dfrac{-83}{8}(x-11)\\\\8(y-12)=-83(x-11)\\\\8y+96=-83x+913\\\\83x+8y=913-96\\\\83x+8y=817[/tex]

Hence, the equation of the line that passes through the points (3, 95) and (11, 12) is 83x + 8y = 817.

To know more about the equation of line click the link given below.

https://brainly.com/question/2564656

Otras preguntas