For this case the centripetal force is given by:
[tex] F = m * (\frac{v^2}{r})
[/tex]
Where,
m: mass of the object
v: tangential speed
r: rope radius
Substituting values in the equation we have:
[tex] F = (4.0) * (\frac{1.8^2}{1.2})
[/tex]
Then, doing the corresponding calculations:
[tex] F = 10.8 N
[/tex]
Answer:
The centripetal force exerted on the rope is:
[tex] F = 10.8 N [/tex]
The centripetal force exerted on the given rope is 10.8 N. The force acting on the object moves in the circular path towards the center of the circle.
The force acting on the object moves in the circular path towards the center of the circle.
[tex]F_c = m\dfrac {v_2}r[/tex]
Where,
[tex]m[/tex] - mass of the object = 4.0 kg
[tex]v[/tex] - tangential speed = 1.8 m/s
[tex]r[/tex] - rope radius = 1.2 m
Put the values in the formula,
[tex]F_c = 4\dfrac {1.8^2}{1.2}\\\\F_c = 10.8 \rm \ N[/tex]
Therefore, the centripetal force acting on the ball is 10.8 N.
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