Let's separate the hexagon into 5 shapes; 2 triangles on each side, and a rectangle in the middle. Now let's find the area of each of the smaller shapes.
Top left triangle:
The equation to find the area of a triangle is
(base = b, height = h, a = area)
a = b · h · [tex] \frac{1}{2} [/tex]
Now let's add in our values and solve.
a = 2 · 4 · [tex] \frac{1}{2} [/tex]
a = 8 · [tex] \frac{1}{2} [/tex]
a = 4
Now since there are 4 of these triangles, and they're all the same size,
4 · 4 = 16
All of the triangles put together = 16cm²
The middle rectangle:
The equation to find the area of a rectangle is simple:
(w = width, l = length, a = area)
a = w · l
Now let's put in our values and solve.
a = 4 · 8
a = 32
The rectangle is 32cm²
Now let's add the areas together.
32 + 16 = 48
The answer is 48cm²
Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
