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vickykinardgodw

The graph of f(x) has a slope of 1/1 and a y intercept of -6.  To graph, place a point at (0,_6).  Then move up 1 and over 1.  This will give another point at (1,-5).  Draw a line through the points.

The graph of g(x) has a slope of 1/1 and a y intercept of 6.  To graph, place a point at (0,6).  Then move up 1 and over 1.  This will give another point at (1,7).  Draw a line through the points

lines are parallel since slopes are the same.

h(x) = x-6+x+6= 2x or 2x+0.  This line has a slope of 2/1 and a y intercept of 0.  To graph, place a point at (0,0).  Then move up 2 and over 1.  This will give another point at (1,2).  Draw a line through the points.

calculista

Answer:

The answer in the attached figure

Step-by-step explanation:

we have

[tex]f(x)=x-6[/tex] -----> equation A

This is a linear equation with slope [tex]m=1[/tex] and a y-intercept equal to [tex]-6[/tex]

[tex]g(x)=x+6[/tex] -----> equation B

This is a linear equation with slope [tex]m=1[/tex] and a y-intercept equal to [tex]6[/tex]

The function f(x) and g(x) are parallel lines

we know that

[tex]h(x)=f(x)+g(x)[/tex]

Substitute

[tex]h(x)=x-6+x+6[/tex]

[tex]h(x)=2x[/tex]

This is a linear equation with slope [tex]m=2[/tex] that passes through the origin ( represent a direct variation)

Using a graphing tool

see the attached figure

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