Respuesta :
The gravitational force exerted by the Earth on an object, and thus the acceleration due to gravity of the object, is inversely proportional to the square of the distance between the center of the Earth and the object.
At the Earth's surface, with mean radius 6380 km, g = 9.81 m/s².
Mean distance of Moon from Earth is 384000 km. (The moon takes quite an elliptical path, and its orbital distance varies from about 363000 km to 407000 km.)
So acceleration due to Earth's gravity at mean lunar orbit = 9.81 * (6380/384000)² = 0.0027 m/s², to 2 significant figures.
At the Earth's surface, with mean radius 6380 km, g = 9.81 m/s².
Mean distance of Moon from Earth is 384000 km. (The moon takes quite an elliptical path, and its orbital distance varies from about 363000 km to 407000 km.)
So acceleration due to Earth's gravity at mean lunar orbit = 9.81 * (6380/384000)² = 0.0027 m/s², to 2 significant figures.
The acceleration due to earth's gravity form a distance equal to orbital radius of the moon = 0.0027 m/s²
Given that :
Orbital radius of the moon = 363000 km
g = 9.81 m/s²
mean radius of earth = 6380 km
Acceleration due to gravity ∝ 1 / ( Δd )²
Therefore acceleration due to gravity from the center of the earth equal to the orbital radius of the moon
= 9.81 * ( 6380 / 363000 )²
≈ 0.0027 m/s²
Hence we can conclude that The acceleration due to earth's gravity from a distance equal to orbital radius of the moon = 0.0027 m/s²
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