The distance can Shawn see to the horizontal is 6.7 miles.
Horizontal distance
The following formula is used to calculate the horizontal distance;
[tex]\rm d=\sqrt{\dfrac{3h}{2}}[/tex]
Given information
Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level.
Wyatt’s eye-level height - h₁ = 120ft is;
[tex]\rm d_1=\sqrt{\dfrac{3h_1}{2}}\\\\\rm d_1=\sqrt{\dfrac{3 \times 120}{2}}\\\\\rm d_1=\sqrt{3\times 60}\\\\\rm d_1=\sqrt{180}\\\\d_1=13.43[/tex]
Shawn’s eye-level height - h₂ = 270ft
[tex]\rm d_2=\sqrt{\dfrac{3h_2}{2}}\\\\\rm d_2=\sqrt{\dfrac{3 \times 270}{2}}\\\\\rm d_2=\sqrt{3\times 135}\\\\\rm d_2=\sqrt{405}}\\\\d_2=20.12[/tex]
The distance can Shawn see to the horizontal is;
[tex]\rm d=d_2-d_1\\\\d=20.12 - 13.42 \\\\ d= 6.7[/tex]
Hence the distance can Shawn see to the horizontal is 6.7 miles.
To know more about horizontal distance click the link given below.
https://brainly.com/question/3780326
