Respuesta :
In a closed system, heat should be conserved which means that the heat produced in the calorimeter is equal to the heat released by the combustion reaction. We calculate as follows:
Heat of the combustion reaction = mC(T2-T1)
= 1 (1.50) (41-21)
= 30 kJ
Heat of the combustion reaction = mC(T2-T1)
= 1 (1.50) (41-21)
= 30 kJ
Answer:
30 kJ is released during the combustion of this sample.
Explanation:
Heat released during combustion = Heat gained by calorimeter
Mass of calorimeter= m = 1.00 kg=1000 g
Change in temperature of the calorimeter = ΔT = 41.0 °C - 21.0 °C =20.0 °C
Specific heat if calorimeter = c = 1.50 J/g °C
Heat released during combustion = Q
[tex]Q=mc\Delta T[/tex]
[tex]Q=1000.00 g\times 1.50 J/g ^oC\times 20.0 ^oC=30,000 =30 kJ[/tex]
30 kJ is released during the combustion of this sample.