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circle O has center (2,6), and passes through the point P (4,3) write the equation of the line that is tangent to circle O at point P

Respuesta :

mreijepatmat
Circle equation :(y-k)² + (x-h)² = R², Given Center coordinates (2,6) =(h,k)

==> (y-2)² +(x-6)² - R²


Find R: Let P the point on the circle at (4,3) so R² = 4² + 3²=> R²= 25
SO THE FINAL EQUATION =>(y-2)² + (x-6)² =25

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