Respuesta :

35.9g x 1 mol/ 2.016g x 22.4 L/ 1 mol= 398.89 L

Answer: 402.08 L

Explanation: According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

[tex]\text{Number of moles}=\frac{35.9 g}{2g/mol}=17.95moles[/tex]

Now 1 mole of [tex]H_2[/tex] molecule occupy= 22.4 L at STP

17.95 moles of [tex]H_2[/tex] molecule contains = [tex]\frac{22.4}{1}\times 17.95=402.08 L[/tex] at STP