Respuesta :
Assuming the lowest point of its path is at a height of 0 m, I would use the concept of conservation of energy:
At the highest point, the pendulum has no kinetic energy since its velocity is zero, so the total energy at that point is:
[tex]E = mgh[/tex]
At the lowest point the potential energy is zero since the height h = 0, and now the energy reads:
[tex]E = \frac{1}{2} m v^{2} [/tex]
Since no energy is lost:
[tex]mgh = \frac{1}{2} m v^{2} [/tex]
Solve for v:
[tex]v = \sqrt{2gh} [/tex]
At the highest point, the pendulum has no kinetic energy since its velocity is zero, so the total energy at that point is:
[tex]E = mgh[/tex]
At the lowest point the potential energy is zero since the height h = 0, and now the energy reads:
[tex]E = \frac{1}{2} m v^{2} [/tex]
Since no energy is lost:
[tex]mgh = \frac{1}{2} m v^{2} [/tex]
Solve for v:
[tex]v = \sqrt{2gh} [/tex]
