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You have a spring gun. the end of the gun is 1 meter above the ground. this gun is shot horizontally with no air resistance. the cannon ball hits the ground 1.32 meters ahead of the gun. what is the cannon ball's initial velocity?

Respuesta :

I used an app called Newtonium to do the calculations. In the figure below you see what I got. Solve for v₀.
Ver imagen Аноним

Here end point of gun is 1 meter above the ground

So the time taken by the bullet to hit the ground will be given as

[tex]y = v_y t + \frac{1}{2} gt^2[/tex]

now given data we have

[tex]v_y = 0[/tex]

[tex]1 = 0 + \frac{1}{2}(9.8)t^2[/tex]

[tex]t = 0.45 s[/tex]

now in the above time the bullet will cover 1.32 m horizontal distance

so here we will have

[tex]d = v_x t[/tex]

[tex]1.32 = v_x (0.45)[/tex]

[tex]v_x = 2.92 m/s[/tex]

so speed of bullet will be 2.92 m/s

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