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A 60.0 kg object is moving east at 8.00 m/s, and then slows down to 4.00 m/s. How much work was done?

Respuesta :

taskmasters
work can be calculated using the formula:
w = 0.5m ( vf^2 - vi^2)
where m is the mass of the object
vf is the final velocity of the object
vi is the initial velocity of the object

w = 0.5 ( 60 ) [ (4^2) - ( 8^2 ) ]
w = -1440 J was the work done by the object

Answer:

-1440

Explanation:

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