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When we see light from a neon sign, we are observing radiation from excited neon atoms. If this radiation has a wavelength of (5.40x10^2) nm, what is the energy of the photon being emitted? Remember to use the correct number of significant figures, put your answer in scientific notation, and include the letter for the units. (Planck's constant h = 6.626 *10-34 Js and speed of light c = 2.998 x108 m/s) Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: Å X10 Answer units

Respuesta :

4.78 × 10^-19 J.

To find the energy of the emitted photon, we can use the formula E = hc÷λ. where E is the energy, h is the Planck constant, c is the speed of light, and λ is the wavelength of the radiation. Plugging in the given values ​​gives:

E = (6.626 × 10^-34 Js)(2.998 × 10^8 m/s)/(5.40 × 10^2 nm)

= 4.78 × 10^-19 J

So the energy of the photon being emitted is 4.78 × 10^-19 J.

Read more about energy of a photon on brainly.com/question/23737904

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