Temperatures in °F can be converted in °C using the formula
C=5(F-32)/9
Make F the subject of the formula
Give your answer in the form aC+b/c where a,b and c are all positive integers

Temperatures in F can be converted in C using the formula C5F329 Make F the subject of the formula Give your answer in the form aCbc where ab and c are all posi class=

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Answer:

Step-by-step explanation:

To make F the subject of the formula, you need to solve for F in the equation C = 5(F-32)/9.

You can do this by first multiplying both sides of the equation by 9 to get rid of the fraction:

C * 9 = 5(F-32)

Then, you can distribute the 5 on the right side of the equation:

C * 9 = 5F - 160

Then, you can add 160 to both sides of the equation to isolate the F term:

C * 9 + 160 = 5F

Finally, you can divide both sides of the equation by 5 to solve for F:

F = (C * 9 + 160)/5

This gives you the final form of the equation:

F = (9C + 160)/5

In this form, F is the subject of the formula. a = 9, b = 160, and c = 5 are all positive integers.

Answer:

[tex]F=\dfrac{9C+160}{5}[/tex]

Step-by-step explanation:

Given equation:

[tex]C=\dfrac{5(F-32)}{9}[/tex]

Multiply both sides by 9:

[tex]\implies 9C=5(F-32)[/tex]

Divide both sides by 5:

[tex]\implies \dfrac{9C}{5}=F-32[/tex]

Add 32 to both sides:

[tex]\implies \dfrac{9C}{5}+32=F[/tex]

[tex]\implies F=\dfrac{9C}{5}+32[/tex]

Rewrite 32 as a fraction with denominator 5:

[tex]\implies F=\dfrac{9C}{5}+\dfrac{32 \cdot 5}{5}[/tex]

[tex]\implies F=\dfrac{9C}{5}+\dfrac{160}{5}[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:[/tex]

[tex]\implies F=\dfrac{9C+160}{5}[/tex]