A rectangle has a length of x inches and a width 2 inches less than the length.

(x - 2) inches

x inches

If the dimensions were doubled, what would be the area, in square inches, of the new rectangle in terms of x?

O 2 - 4

O 8-8

O 2r? - 42

O4r? - 8

Respuesta :

The area of the rectangle newly formed in terms of x is [tex]4x^{2} -8x[/tex] square inches

According to the question,

We have the following information:

A rectangle has a length of x inches and a width 2 inches less than the length.

Width of the rectangle = (x - 2) inches

Length of the rectangle = x inches

Now, when the dimensions are doubled:

Width = 2(x-2) inches

Length = 2x inches

Following formula is used to find the area of rectangle:

Area = length*breadth

Area = 2x*2(x-2)

Area of the rectangle = 4x(x-2)

Area of the rectangle = [tex]4x^{2} -8x[/tex] square inches

Hence, the correct option is D.

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