ny2k
ny2k
18-02-2017
Mathematics
contestada
What is the y value of the vertex?
y=x^2-10x+24
Respuesta :
apologiabiology
apologiabiology
18-02-2017
hack way
find x value then plug back
to find the x value of the vertex in form
y=ax^2+bx+c
the x value is -b/(2a)
so
y=1x^2-10x+24
x value is -10/(2*1)=-10/2=5
sub back
y=5^2-10(5)+24
y=25-50+24
y=25+24
y=49
y value is 49
Answer Link
thronyslayer22
thronyslayer22
18-02-2017
x from -6 to 25, y from -50 to 10, x^2 -10x -24
vertex=(5,-49)
x intercept=-2 & 12
y intercept=-24
Answer Link
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