Respuesta :
Answer: [tex]f^{-1}(x)=\frac{x+12}{4}[/tex]
Step-by-step explanation:
Let f(y)=x
[tex]x=4y-12\\\\x+12=4y\\\\y=\frac{x+12}{4}\\\\f^{-1}(x)=\frac{x+12}{4}[/tex]
Answer: [tex]f^{-1}(x)=\frac{x+12}{4}[/tex]
Step-by-step explanation:
Let f(y)=x
[tex]x=4y-12\\\\x+12=4y\\\\y=\frac{x+12}{4}\\\\f^{-1}(x)=\frac{x+12}{4}[/tex]