In circle SS, ST=5ST=5 and m\angle TSU=50^\circ∠TSU=50∘ Find the length of \overset{\LARGE\frown}{TU} TU⌢ . Express your answer as a fraction times \piπ.

The length of arc TU, as a fraction terms of π, is calculated as: 25/18 π units.
The length of an arc of a circle is the distance around the portion of the circumference of a circle that is marked by two points connected to the radius of the circle. Given r as the radius length and ∅ is the central angle measure, the length of the arc of the circle can be calculated as:
Arc length = ∅/360 × 2 × π × r.
Given the following:
Central angle (∅) = m∠TSU = 50°
Radius of the circle (r) = 5
Plug the values into ∅/360 × 2 × π × r:
Arc length = 50/360 × 2 × π × 5
Arc length = (50 × 2 × π × 5)/360
Arc length = 500/360 × π
Arc length = 50/36 × π
Arc length = 25/18 × π
Arc length of TU = 25/18 π units
Thus, the length of arc TU, as a fraction terms of π, is calculated as: 25/18 π units.
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