Respuesta :
The mutual inductance of the two coils come out to be 1.1 x 10⁻³ H.
What is mutual inductance?
When two wire coils are brought near enough together that the magnetic field through one links with the magnetic field on the other, the voltage is formed in the second coil. When a voltage is applied to one coil, it induces a voltage in the other. This is known as mutual inductance.
Now, for the given values of;
Rate of current in coil 1 is 5.6 a/s.
The emf is 6.0 x 10⁻³ V
According to the mutual inductance of a coil, the flux coupled to coil 2 goes proportional to the current flowing in coil 1.
As a result, we will have
[tex]\phi_{2}=M i_{1}[/tex]
We know from this that the rate of change of flux is equivalent to the EMF created in the coil.
As a result, we will have
[tex]\frac{d \phi_{2}}{d t}=M \frac{d i_{1}}{d t}[/tex]
This equation in terms of emf is;
[tex]E M F=M \frac{d i}{d t}[/tex]
Substituting the values in the above equation;
6.0 x 10⁻³ = M×5.6
M = 1.1 x 10⁻³ H.
Therefore, the mutual inductance of the two coils is 1.1 x 10⁻³ H.
To know more about mutual inductance, here
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