The ratio of the new power to the old power would be 2:1.
The rate of doing work is known as power. The Si unit of power is the watt.
Power =work/time
The mathematical expression for the electric power is as follows
P = VI
As we know from Ohm's law V=IR
By substituting the value of current I= V/R
P= V²/R
As given in the question Power is delivered to a resistor of resistance,If the resistance is doubled while the voltage is adjusted such that the current is constant,
Pnew = (2V)²/2R
= 2P
Pnew/P = 2/1
Thus, the ratio of the new power delivered to the old power comes out to be 2:1.
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